Implement Stack using Queues
Implement a last-in-first-out (LIFO) stack using only two queues. The implemented stack should support all the functions of a normal stack (push
, top
, pop
, and empty
).
Implement the MyStack
class:
void push(int x)
Pushes element x to the top of the stack.int pop()
Removes the element on the top of the stack and returns it.int top()
Returns the element on the top of the stack.boolean empty()
Returns true
if the stack is empty, false
otherwise.Notes:
push to back
, peek/pop from front
, size
and is empty
operations are valid.Input
["MyStack", "push", "push", "top", "pop", "empty"]
[[], [1], [2], [], [], []]
Output
[null, null, null, 2, 2, false]
Explanation
MyStack myStack = new MyStack();
myStack.push(1);
myStack.push(2);
myStack.top(); // return 2
myStack.pop(); // return 2
myStack.empty(); // return False
Constraints:
1 <= x <= 9
At most 100 calls will be made to push, pop, top, and empty.
All the calls to pop and top are valid.
解法:
實作陣列的類別功能
class MyStack {
array: number[] = [];
constructor() {}
push(x: number): void {
this.array.push(x);
}
pop(): number {
return this.array.pop();
}
top(): number {
if(this.array.length){
return this.array[this.array.length - 1];
}else{
return null;
}
}
empty(): boolean {
return !!!this.array.length;
}
}